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Lagrangian actions on 3-body problems with two fixed centers
Boundary Value Problems volume 2012, Article number: 28 (2012)
In this paper, we study the existence of figure "∞"-type periodic solution for 3-body problems with strong-force potentials and two fixed centers, and we also give some remarks in the case with Newtonian weak-force potentials.
Mathematical Subject Classification 2000: 34C15; 34C25; 70F10.
1 Introduction and Main Result
We assume two masses are fixed at and , the third mass m3 is affected by m1 and m2 and moving according to the Newton's second law and the general gravitational law [1, 2], then the position q(t) for m3 satisfies
Here we want to use variational minimizing method to look for periodic solution for m3 which winds around q1 and q2, let
Theorem 1.1 For α ≥ 2, the minimizer of f(q) on does exist and is non-collision "∞"-type periodic solution of (1.1)-(1.3).(See Figure 1)
2 The Proof of Theorem 1.1
Using Palais'S symmetrical Principle , it's easy to prove the following variational Lemma:
Lemma 2.1 The critical point of f(q) in Λ is the noncollision periodic solution winding around q1 counter-clockwise and q2 clockwise one time during one period.
Lemma 2.2 If x ∈ W1,2 (ℝ/ℤ, ℝ2) and ∃ t0 ∈ [0,1], s.t. x(t0) = 0, if α ≥ 2 and a > 0, then
It's easy to see
Lemma 2.3 is a weakly closed subset of the Hilbert space W1,2(ℝ/ℤ, ℝ2).
Lemma 2.4 f(q) is coercive and weakly lower-semicontinuous on the closure of Λ.
Proof. By q(-t) = -q(t) and q(t) ∈ W1,2(ℝ/ℤ, ℝ2), we have . By Wirtinger's inequality, we know f(q) is coercive. By Sobolev's embedding Theorem and Fatou's Lemma, f is weakly lower-semi-continuous on the weakly closed set of W1,2.
Lemma 2.5 Let X be a reflexive Banach space,M ⊂ X be weakly closed subset,f : M → R be weakly lower semi-continous and coercive (f(x) → +∞ as ∥x∥ → +∞), then f attains its infimum on M.
According to Lemmas 2.1-2.5, we know that f(q) attains its infimum on and the minimizer of f(q) on is collision-free since if let x1 = q - q1, x2 = q - q2, then
So if the minimizer of f(q) on has collision at some moment, then Gordon's Lemma tell us the minimum value is +∞ which is a contradiction.
The most interesting case α = 1 is the case for Newtonian potential, we try to prove the minimizer is collision-free, but it seems very difficult, here we give some remarks.
Lemma 2.6 If y(0) = 0 and 2k is an even positive integer, then
There is equality only for a certain hyperelliptic curve.
Now we estimate the lower bound of the Lagrangian action f(q) on "∞"-type collisionorbits. Since and , so
If q(t) collides with q1 at some moment t0 ∈ [0,1], without loss of generality, we assume t0 = 0, then q(0) - q1 = 0, we let x(t) = q(t) - q1, y(t) = |x(t)|, then x(0) = 0,y(0) = 0. By Jensen's inequality and Hardy-Littlewood-pólya inequality , we have
Let , then , that is φ is strictly convex.
Let φ'(s) = 0, we solve it to get is the critical point for φ(s), and , which is the maximum value for φ(s) on s > 0 since φ is convex and φ(s) → +∞ as s → 0+.
If we can find the test orbit such that
then the minimizer of f(q) on is collision-free.
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The authors would like to thank the anonymous referees for their valuable suggestions which improve this work. This work was supported by Scientific Research Fund of Sichuan Provincial Education Department (11ZA172).
The authors declare that they have no competing interests.
All authors read and approved the final manuscript.
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Wang, Xr., He, S. Lagrangian actions on 3-body problems with two fixed centers. Bound Value Probl 2012, 28 (2012). https://doi.org/10.1186/1687-2770-2012-28
- 3-body problems with two fixed centers
- "∞"-type solutions
- Lagrangian actions