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Noncommutativity of mappings in hybrid fixed point results
Boundary Value Problemsvolume 2013, Article number: 145 (2013)
Abstract
In this note, some coincidence and common fixed points of nonlinear hybrid mappings have been obtained under certain noncommutativity conditions of mappings. Our results improve several known results in the field of hybrid fixed point theory.
MSC:54H25, 47H10, 54C60.
Introduction
As a generalization of the Banach fixed point theorem, Nadler’s contraction principle has lead to an excellent fixed point result in the area of nonlinear analysis. Some other works focused on fixed point results for multivalued mappings are, for instance, [1–5]. Coincidence and common fixed points of nonlinear hybrid contractions (i.e., contractions involving singlevalued and multivalued mappings) have been recently studied by many authors. To mention some of the achievements, we cite, for example, [6–12].
The concept of commutativity of singlevalued mappings [13] was extended in [14] to the setting of a singlevalued mapping and a multivalued mapping on a metric space. This concept of commutativity has been further generalized by different authors, viz weakly commuting [15], compatible [16], weakly compatible [8]. It is interesting to note that in all the results obtained so far concerning common fixed points of hybrid mappings the (singlevalued and multivalued) mappings under consideration satisfy either the commutativity condition or one of its generalizations (see, for instance, [6–10]). In this note, we show the existence of fixed points of hybrid contractions which do not satisfy any of the commutativity conditions or its abovementioned generalizations. Our result extends and improves several wellknown results in the field of hybrid fixed point theory. Some other recent related references are [17, 18], where common fixed point theorems for hybrid mappings on a symmetric space are proved under the assumptions of weak compatibility and occasional weak compatibility. Some analogous results for the case of contractivity conditions of integral type are presented in [19–21] and generalized contractive hybrid pairs are considered in [22]. Finally, in [23], fixed point results are proved in topological vector space valued cone metric spaces (with nonnormal cones).
Preliminaries
For a metric space $(X,d)$, let $(CB(X),H)$ and $(CL(X),H)$ denote respectively the hyperspace of nonempty closed bounded and nonempty closed subsets of X, where H is the Hausdorff metric induced by d. For $f:X\to X$ and $T:X\to CL(X)$, we shall use the following notations:
and
We recall some definitions.
Definition 1 Mappings f and T are said to be commuting at a point $x\in X$ if $fTx\subseteq Tfx$. The mappings f and T are said to be commuting on X if $fTx\subseteq Tfx$ for all $x\in X$.
Definition 2 Mappings f and T are said to be weakly commuting at a point $x\in X$ if
The mappings f and T are said to be weakly commuting on X if
for all $x\in X$.
Definition 3 The mappings f and T are said to be compatible if $fTx\in CB(X)$ for all $x\in X$ and ${lim}_{n\to +\mathrm{\infty}}H(Tf{x}_{n},fT{x}_{n})=0$, whenever $\{{x}_{n}\}$ is a sequence in X such that $T{x}_{n}\to M\in CB(X)$ and $f{x}_{n}\to t\in M$, as $n\to +\mathrm{\infty}$.
Definition 4 The mappings f and T are said to be fweak compatible if $fTx\in CB(X)$ for all $x\in X$ and the following limits exist and satisfy the inequalities:

(i)
${lim}_{n\to \mathrm{\infty}}H(Tf{x}_{n},fT{x}_{n})\le {lim}_{n\to \mathrm{\infty}}H(Tf{x}_{n},T{x}_{n})$,

(ii)
${lim}_{n\to \mathrm{\infty}}d(fT{x}_{n},f{x}_{n})\le {lim}_{n\to \mathrm{\infty}}H(Tf{x}_{n},T{x}_{n})$,
whenever $\{{x}_{n}\}$ is a sequence in X such that $T{x}_{n}\to M\in CB(X)$ and $f{x}_{n}\to t\in M$ as $n\to \mathrm{\infty}$.
Let $C(T,f)$ denote the set of all coincidence points of the mappings f and T, that is, $C(T,f)=\{u:fu\in Tu\}$.
Definition 5 The mappings f and T are said to be coincidentally commuting if they commute at their coincidence points.
Definition 6 Mappings f and T are said to be coincidentally idempotent if $ffu=fu$ for every $u\in C(T,f)$, that is, if f is idempotent at the coincidence points of f and T.
Definition 7 Mappings f and T are said to be occasionally coincidentally idempotent (or, in brief, oci) if $ffu=fu$ for some $u\in C(T,f)$.
It should be remarked that coincidentally idempotent pairs of mappings are occasionally coincidentally idempotent, but the converse is not necessarily true as shown in Example 18 of this note.
Main results
We recall the following lemma.
Lemma 8 [8]
Let $T:Y\to CB(X)$ and $f:Y\to X$ be fweak compatible. If $\{fw\}=Tw$ for some $w\in Y$ and $H(Tx,Ty)\le h(a\cdot L(x,y)+(1a)\cdot N(x,y))$ for all x, y in Y, where $0<h<1$, $0\le a\le 1$, then $fTw=Tfw$.
We remark that the abovementioned lemma has been used in [8, 9] and [10] to prove the existence of fixed points of hybrid mappings. However, we have noticed some typos in its original statement which have been rectified in the above statement without altering the proof.
Next, we prove a fixed point result for hybrid mappings under a general integraltype contractivity condition. In contrast to [20], we avoid the complete character of the base space X, and we introduce hybrid mappings. With respect to the study in [21], we consider here occasionally coincidentally idempotent mappings.
Theorem 9 Let Y be an arbitrary nonempty set, $(X,d)$ be a metric space, $f:Y\to X$ and $T:Y\to CB(X)$ be such that
that is, ${\bigcup}_{y\in Y}T(y)\subseteq f(Y)$,
$\psi :{\mathbb{R}}_{+}\to {\mathbb{R}}_{+}$ is a Lebesgue measurable mapping which is nonnegative, summable on each compact interval and such that
which trivially implies that
and
Suppose also that
where $\gamma :(1,+\mathrm{\infty})\u27f6{\mathbb{R}}_{+}$ is such that
and
Then T and f have a coincidence point. Further, if f and T are occasionally coincidentally idempotent, then f and T have a common fixed point.
Proof In view of (1) and Nadler’s remark in [24], given the point ${x}_{0}\in Y$, we can construct two sequences $\{{x}_{n}\}$ in Y and $\{{y}_{n}\}$ in X such that, for each $n\in \mathbb{N}$,
Indeed, since $T{x}_{0}\subseteq f(Y)$, there exists ${x}_{1}\in Y$ such that $f{x}_{1}={y}_{1}\in T{x}_{0}$. Besides, given ${y}_{1}\in T{x}_{0}$, by Nadler’s remark in [24] and using that ${q}^{1/2}>1$, we can choose ${y}_{2}\in T{x}_{1}\subseteq f(Y)$ such that $d({y}_{1},{y}_{2})\le {q}^{1/2}\cdot H(T{x}_{0},T{x}_{1})$ and ${y}_{2}=f{x}_{2}$ for a certain ${x}_{2}\in Y$. The continuation of this process allows to construct the two abovementioned sequences $\{{x}_{n}\}$ and $\{{y}_{n}\}$ inductively.
We claim that $\{{y}_{n}\}$ is a Cauchy sequence. Using the inequality in (2) and also property (7), which is trivially valid for $\u03f5=0$, it follows, for $n\ge 2$, that
where
Suppose that
where $\lambda =\gamma ({q}^{1/2})\cdot q\in (0,1)$, hence $d(f{x}_{n1},f{x}_{n})>0$ and
so that
where we have also used (6) (a consequence of (4)), (7), (8) and (9). The previous inequalities imply that
which is a contradiction. In consequence,
where $\lambda =\gamma ({q}^{1/2})\cdot q\in (0,1)$, by hypothesis, and hence $\{f{x}_{n}\}$ is a Cauchy sequence in $f(Y)$. This is clear from the following inequality, valid for $n,m\in \mathbb{N}$, $n>m$,
which tends to zero as $m\to +\mathrm{\infty}$.
Since $f(Y)$ is complete, then the sequence $\{f{x}_{n}\}$ has a limit in $f(Y)$, say u. Let $w\in {f}^{1}(u)$ and prove that $fw\in Tw$.
Suppose that $fw\notin Tw$, then, by (2), we have
where
Here, we have used that $d(f{x}_{n},fw)=d(f{x}_{n},u)\to 0$, as $n\to +\mathrm{\infty}$, $d(f{x}_{n},T{x}_{n})\le d(f{x}_{n},f{x}_{n+1})\to 0$, as $n\to +\mathrm{\infty}$, $d(fw,Tw)>0$ due to $fw\notin Tw$ and Tw closed, and
Hence, for n large enough, we have
Making n tend to +∞ in the previous inequality, we have
and, therefore, since $q<1$ and $d(fw,Tw)>0$, we get ${\int}_{0}^{d(fw,Tw)}\psi (t)\phantom{\rule{0.2em}{0ex}}dt<{\int}_{0}^{d(fw,Tw)}\psi (t)\phantom{\rule{0.2em}{0ex}}dt$, which is a contradiction. Hence $fw\in Tw$, that is, w is a coincidence point for T and f.
Although this fact is not relevant to the proof, we note that $H(T{x}_{n1},T{x}_{n})\to 0$ since
Indeed,
where
therefore
Then ${lim}_{n\to +\mathrm{\infty}}{\int}_{0}^{H(T{x}_{n1},T{x}_{n})}\psi (t)\phantom{\rule{0.2em}{0ex}}dt=0$ and, by the properties of ψ, we get $H(T{x}_{n1},T{x}_{n})\to 0$ as $n\to +\mathrm{\infty}$. From the definition of $\{{y}_{n}\}$, we deduce that $d(f{x}_{n},T{x}_{n})\le H(T{x}_{n1},T{x}_{n})$ for every n and, therefore, ${lim}_{n\to \mathrm{\infty}}d(f{x}_{n},T{x}_{n})=0$, so that $\{{x}_{n}\}$ is asymptotically Tregular with respect to f. However, this property can be deduced directly from the fact that
Now, if f and T are occasionally coincidentally idempotent, then $ffw=fw$ for some $w\in C(T,f)$. Then we have
where
If $Tfw\ne Tw$, then from inequality (10) and using (5) (which is guaranteed by (4)), we have that
which is a contradiction. Hence $Tfw=Tw$. Thus we have $fw=ffw$ and $fw\in Tw=Tfw$, i.e., fw is a common fixed point of f and T. □
Let Φ denote the family of maps ϕ from the set ${\mathbb{R}}_{+}$ of nonnegative real numbers to itself such that
Corollary 10 Let Y be an arbitrary nonempty set, $(X,d)$ be a metric space, $f:Y\to X$ and $T:Y\to CB(X)$ be such that $T(Y)\subseteq f(Y)$,
for all x, y in Y, where $\varphi \in \mathrm{\Phi}$ (satisfying (11) for a certain $q\in (0,1)$),
$\psi :{\mathbb{R}}_{+}\to {\mathbb{R}}_{+}$ is a Lebesgue measurable mapping which is nonnegative, summable on each compact interval and such that (4) holds. Suppose also that (7), (8) and (9) hold for a certain $\gamma :(1,+\mathrm{\infty})\u27f6{\mathbb{R}}_{+}$ and q determined by (11). Then T and f have a coincidence point. Further, if f and T are occasionally coincidentally idempotent, then f and T have a common fixed point.
Proof It is a consequence of Theorem 9 since (11) and (12) imply that
for all x, y in Y and $q\in (0,1)$. □
Remark 11 The condition
implies the validity of hypothesis (7) in Theorem 9 for the particular case of γ the identity mapping. Moreover, for $0<q<1$, hypotheses (8) and (9) are trivially satisfied for this choice of γ. Indeed, using that $0<q<1$, we get
and
Remark 12 Assuming (8), condition (9) is trivially valid if $\lambda \cdot \gamma (\frac{1}{\lambda})\le 1$ for every $\lambda \in (0,1)$ or, equivalently, $\gamma (\frac{1}{\lambda})\le \frac{1}{\lambda}$ for every $\lambda \in (0,1)$, that is, $\gamma (z)\le z$ for every $z>1$. Note that this last condition is trivially valid for γ the identity mapping. Moreover, if $\gamma (z)\le z$ for every $z>1$, then $\gamma (z)<{z}^{2}$ for every $z>1$ and, therefore, if $q\in (0,1)$, then $\gamma ({q}^{1/2})<{q}^{1}$, obtaining (8) if $\gamma ({q}^{1/2})>0$.
Remark 13 According to Remark 12, for $q\in (0,1)$ fixed and ψ satisfying (4), an admissible function γ can be obtained by taking
provided that $\gamma ({q}^{1/2})>0$ and $\gamma (z)\le z$ for every $z>1$.
Example 14 Taking ψ as the constant function $\psi (t)=K>0$, $t>0$, in the statement of Theorem 9, condition (7) is reduced to
so that we must choose γ as a nonnegative function satisfying that $\gamma (z)=z$ for $z>1$ (obviously, $\gamma ({q}^{1/2})>0$ since $q\in (0,1)$) in order to guarantee conditions (7), (8) and (9).
Example 15 A simple calculation provides that, for the function $\psi (t)=t$, $t>0$, condition (7) is written as $\gamma (z)\ge {z}^{2}$ for $z>1$ and, therefore, in this case condition (8) is never fulfilled. If we take $\psi (t)=K{t}^{m}$, $t>0$, for $K>0$ and $m>0$ fixed, then (7) implies that $\gamma (z)\ge {z}^{m+1}>z$ for $z>1$.
Example 16 Now, we choose $\psi (t)=K{t}^{m}$, $t>0$, where $K>0$ and $1<m<0$ are fixed. Note that the case $m=0$ has already been studied in Example 14. In this case $1<m<0$, condition (7) is reduced to
which is equivalent to $\gamma (z)\ge {z}^{m+1}$ for $z>1$. Note that this inequality implies, for $0<q<1$, that $\gamma ({q}^{1/2})>0$. If we add the hypothesis $\gamma (z)\le z$ for $z>1$, then we guarantee the validity of conditions (8) and (9) due to Remark 12. Hence, we can take any nonnegative function γ satisfying that
Of course, $\gamma (z)=z$ and $\gamma (z)={z}^{m+1}$ are valid choices.
Example 17 Take $\psi (t)={e}^{t}$, $t>0$. Condition (7) is equivalent to
that is,
Now, for each $z>1$ fixed, we calculate ${sup}_{\u03f5>0}\frac{1{e}^{z\u03f5}}{1{e}^{\u03f5}}$, which is obviously positive, and we check that its value is equal to z.
It is easy to prove that for $z>1$ fixed, the function $\u03f5\in (0,+\mathrm{\infty})\u27f6{\mathcal{R}}_{z}(\u03f5)=\frac{1{e}^{z\u03f5}}{1{e}^{\u03f5}}$ is decreasing on $(0,+\mathrm{\infty})$. Indeed, the sign of its derivative coincides with the sign of the function $\nu (\u03f5)=z{e}^{z\u03f5}(1{e}^{\u03f5})(1{e}^{z\u03f5}){e}^{\u03f5}$ and also with the sign of $\tau (\u03f5)=z{e}^{z\u03f5}({e}^{\u03f5}1)+{e}^{z\u03f5}1$ for $\u03f5\in (0,+\mathrm{\infty})$. Now, the function τ is strictly negative on $(0,+\mathrm{\infty})$ since $\tau (0)=\tau ({0}^{+})=0$ and ${\tau}^{\prime}(\u03f5)=z(1z){e}^{z\u03f5}({e}^{\u03f5}1)<0$ for $\u03f5>0$.
Moreover, ${lim}_{\u03f5\to {0}^{+}}{\mathcal{R}}_{z}(\u03f5)=z$ for each $z>1$; in consequence, ${sup}_{\u03f5>0}{\mathcal{R}}_{z}(\u03f5)=z$ for every $z>1$. Therefore, if $\gamma (z)\ge z$ for every $z>1$, then (7) follows. Note also that if $q\in (0,1)$, then $\gamma ({q}^{1/2})>0$. Finally, for $q\in (0,1)$, if we take $\gamma :(1,+\mathrm{\infty})\u27f6{\mathbb{R}}_{+}$ such that $\gamma (z)=z$ for $z>1$, we deduce the validity of (7), (8) and (9).
The following example shows that Theorem 9 is a proper generalization of the fixed point results in [7–10].
Example 18 Let $X={\mathbb{R}}_{+}$ be endowed with the Euclidean metric, let $f:X\to X$ and $T:X\to CB(X)$ be defined by $fx=4({x}^{2}+x)$ and $Tx=[0,{x}^{2}+7]$. Let $\varphi :{\mathbb{R}}_{+}\to {\mathbb{R}}_{+}$ be defined by $\varphi (t)=\frac{1}{4}t$ for all $t\in {\mathbb{R}}_{+}$. Then mappings f and T are not commuting and also do not satisfy any of its generalizations, viz weakly commuting, compatibility, weak compatibility. Also the mappings f and T are not coincidentally commuting. Note that $f1\in T1$, but $ff1\ne f1$ and so f and T are not coincidentally idempotent, but $f0\in T0$ and $ff0=f0$ thus f and T are occasionally coincidentally idempotent. For all x and y in X, we have
Note that these inequalities are valid if
which is satisfied taking, for instance, the constant function $\psi \equiv 1$. On the other hand, γ is chosen as the identity map and it satisfies (8) and (9).
Note that 0 is a common fixed point of f and T. We remark that the results of [7–9] and [10] cannot be applied to these mappings f and T.
Theorem 19 In Theorem 9, we can assume, instead of condition (2), one of the inequalities
or
where $a,b\ge 0$, $a+b\le 1$ and $q\in (0,1)$.
Similarly, in Corollary 10, we can consider one of the contractivity conditions
or
where $a,b\ge 0$, $a+b\le 1$ and $\varphi \in \mathrm{\Phi}$ (satisfying (11) for a certain $q\in (0,1)$) and the conclusion follows.
Proof It follows from the inequality
and the nonnegative character of a, b and ψ. Indeed, ${d}^{2}(fx,fy)\le {[L(x,y)]}^{2}$,
hence, for instance,
Note that, in cases (16) and (17), it is not necessary to assume the nondecreasing character of the function ϕ since, using that $\varphi \in \mathrm{\Phi}$, we deduce (14) and (15), respectively. □
Of course, the function $\varphi \equiv 0$ is admissible in the results of this paper.
Note that, taking $a=1$ and $b=0$ in the inequalities of Theorem 19, we obtain the corresponding contractivity conditions of Theorem 9 and Corollary 10. On the other hand, taking $a=0$ and $b=1$ in Theorem 19, we have the following results, which are also corollaries of Theorem 9.
Corollary 20 Let Y be an arbitrary nonempty set, $(X,d)$ be a metric space, $f:Y\to X$ and $T:Y\to CB(X)$ be such that conditions (1), (3) hold and
where $0<q<1$ and $\psi :{\mathbb{R}}_{+}\to {\mathbb{R}}_{+}$ is a Lebesgue measurable mapping which is nonnegative, summable on each compact interval and such that (4) holds. Assume also that (7), (8) and (9) are fulfilled for a certain $\gamma :(1,+\mathrm{\infty})\u27f6{\mathbb{R}}_{+}$. Then f and T have a coincidence point. Further, if f and T are occasionally coincidentally idempotent, then f and T have a common fixed point.
Corollary 21 Let Y be an arbitrary nonempty set, $(X,d)$ be a metric space, $f:Y\to X$ and $T:Y\to CB(X)$ be such that conditions (1), (3) hold and
where $\varphi \in \mathrm{\Phi}$ (satisfying (11) for $q\in (0,1)$) and $\psi :{\mathbb{R}}_{+}\to {\mathbb{R}}_{+}$ is a Lebesgue measurable mapping which is nonnegative, summable on each compact interval and such that (4) holds. Assume also that (7), (8) and (9) are fulfilled for a certain $\gamma :(1,+\mathrm{\infty})\u27f6{\mathbb{R}}_{+}$. Then f and T have a coincidence point. Further, if f and T are occasionally coincidentally idempotent, then f and T have a common fixed point.
Let $\eta :[0,\mathrm{\infty})\to [0,1)$ be a function having the following property (see, for instance, [6, 25]):
($\mathcal{P}$) For $t\ge 0$, there exist $\delta (t)>0$, $s(t)<1$ such that $0\le rt<\delta (t)$ implies $\eta (r)\le s(t)$.
This property obviously holds if η is continuous since η attains its maximum (less than 1) on each compact $[t,t+\delta (t)]$.
Definition 22 A sequence $\{{x}_{n}\}$ is said to be asymptotically Tregular with respect to f if ${lim}_{n\to \mathrm{\infty}}d(f{x}_{n},T{x}_{n})=0$.
The following theorem is related to the main results of Hu [[25], Theorem 2], Jungck [14], Kaneko [26], Nadler [[24], Theorem 5] and Beg and Azam [[6], Theorem 5.4 and Corollary 5.5].
Theorem 23 Let Y be an arbitrary nonempty set, $(X,d)$ be a metric space, $f:Y\to X$ and $T:Y\to CL(X)$ be such that condition (1) holds and
for all $x,y\in Y$, where $\eta :[0,\mathrm{\infty})\to [0,1)$ satisfies ($\mathcal{P}$) and $\psi \ge 0$ is nonincreasing.
Suppose also that Tx is a compact set for every $x\in Y$.
If $f(Y)$ is complete, then

(i)
there exists an asymptotically Tregular sequence $\{{x}_{n}\}$ with respect to f in Y,

(ii)
f and T have a coincidence point.
Further, if f and T are occasionally coincidentally idempotent, then f and T have a common fixed point.
Proof For some ${x}_{0}$ in Y, let ${y}_{0}=f{x}_{0}$ and choose ${x}_{1}$ in Y such that ${y}_{1}=f{x}_{1}\in T{x}_{0}$. Then, by (20), we have
Using (1), we can choose ${x}_{2}\in Y$ such that ${y}_{2}=f{x}_{2}\in T{x}_{1}$ and satisfying that
hence
Note that, in the previous inequalities, we have used that $d(f{x}_{0},f{x}_{1})>0$. If $d(f{x}_{0},f{x}_{1})=0$, then $f{x}_{0}=f{x}_{1}\in T{x}_{0}$ and $\{{x}_{n}\}$ is asymptotically Tregular with respect to f.
By induction, we construct a sequence $\{{x}_{n}\}$ in Y and $\{{y}_{n}\}$ in $f(Y)$ such that, for every n,
and ${y}_{n}=f{x}_{n}\in T{x}_{n1}$.
Also, we have
It follows that the sequence $\{d({y}_{n},{y}_{n+1})\}$ is decreasing and converges to its greatest lower bound, say t. Clearly $t\ge 0$. If $t>0$, then by the property ($\mathcal{P}$) of η, there will exist $\delta (t)>0$ and $s(t)<1$ such that
For this $\delta (t)>0$, there exists $N\in \mathbb{N}$ such that $0\le d({y}_{n},{y}_{n+1})t<\delta (t)$, whenever $n\ge N$. Hence $\eta (d({y}_{n},{y}_{n+1}))\le s(t)$, whenever $n\ge N$. Let $K=max\{\eta (d({y}_{0},{y}_{1})),\eta (d({y}_{1},{y}_{2})),\dots ,\eta (d({y}_{N1},{y}_{N})),s(t)\}$. Then for $n=1,2,3,\dots $ , we have
which contradicts the assumption that $t>0$. Thus ${lim}_{n\to \mathrm{\infty}}d({y}_{n},{y}_{n+1})=0$; i.e., $d(f{x}_{n},T{x}_{n})\to 0$ as $n\to +\mathrm{\infty}$. Hence the sequence $\{{x}_{n}\}$ is asymptotically Tregular with respect to f.
We claim that $\{f{x}_{n}\}$ is a Cauchy sequence. Let $n,m\in \mathbb{N}$ with $n<m$, then, by the nonincreasing character of ψ, we get
Now, we recall that
for every n, which implies that
Following this procedure, we prove that
Therefore,
We check that the righthand side in the last inequality tends to 0 as $n,m\to +\mathrm{\infty}$. Since ${\int}_{0}^{d({y}_{n},{y}_{n+1})}\psi (t)\phantom{\rule{0.2em}{0ex}}dt\to 0$ as $n\to +\mathrm{\infty}$, it suffices to show that ${\sum}_{i=n+1}^{m1}{\prod}_{l=n}^{i1}\eta (d({y}_{l},{y}_{l+1}))$ is bounded (uniformly on n, m). Indeed, we check that ${\sum}_{i=n+1}^{m1}{\prod}_{l=n}^{i1}\eta ({z}_{l})$ is bounded for any sequence $\{{z}_{l}\}$ with nonnegative terms and tending to 0 as $l\to +\mathrm{\infty}$, using the property ($\mathcal{P}$) of the function η. Given $t=0$, by ($\mathcal{P}$), there exist $\delta (0)>0$, ${s}_{0}<1$ such that $0\le r<\delta (0)$ implies $\eta (r)\le {s}_{0}$. Since $\{{z}_{l}\}\to 0$, given $\delta (0)>0$, there exists ${l}_{0}\in \mathbb{N}$ such that, for every $l\ge {l}_{0}$, we have $0\le {z}_{l}<\delta (0)$. This implies that $\eta ({z}_{l})\le {s}_{0}$ for every $l\ge {l}_{0}$.
In consequence, for $n\ge {l}_{0}$, we get
and this expression is bounded independently of m, n.
Hence $\{f{x}_{n}\}$ is a Cauchy sequence in $f(Y)$. Since $f(Y)$ is complete, $\{f{x}_{n}\}$ converges to some p in $f(Y)$. Let $z\in {f}^{1}(p)$. Then $fz=p$. Next, we have
Letting $n\to \mathrm{\infty}$, we get ${\int}_{0}^{d(fz,Tz)}\psi (t)\phantom{\rule{0.2em}{0ex}}dt\le 0$. Thus we have $d(fz,Tz)=0$. Hence $fz\in Tz$.
Now, if f and T are occasionally coincidentally idempotent, then $ffw=fw$ for some $w\in C(T,f)$. Then we have
Thus, $Tfw=Tw$. It follows that $ffw=fw\in Tw=Tfw$. Hence, fw is a common fixed point of T and f. □
Now we state some fixed point theorems for Kannantype multivalued mappings which extend and generalize the corresponding results of Shiau et al. [10] and Beg and Azam [6, 27]. A proper blend of the proof of Theorem 9 and those of [[10], Th. 6, Th. 7, Th. 8 respectively] and [[9], Theorems 3.1, 3.2, 3.3] will complete the proof.
Theorem 24 Let Y be an arbitrary nonempty set, $(X,d)$ be a metric space, $f:Y\to X$ and $T:Y\to CB(X)$ be such that (1) holds and
for all $x,y\in Y$, where ${\alpha}_{i}:{\mathbb{R}}_{+}\to [0,1)$ ($i=1,2$) are bounded on bounded sets, r is some fixed positive real number and $\psi :{\mathbb{R}}_{+}\to {\mathbb{R}}_{+}$ is a Lebesgue measurable mapping which is summable on each compact interval and ${\int}_{0}^{\u03f5}\psi (t)\phantom{\rule{0.2em}{0ex}}dt>0$ for each $\u03f5>0$. Suppose that there exists an asymptotically Tregular sequence $\{{x}_{n}\}$ with respect to f in Y. If $T(Y)$ is complete or
then f and T have a coincidence point. Further, if f and T are occasionally coincidentally idempotent, then f and T have a common fixed point.
Proof By hypotheses,
Since $\{{x}_{n}\}$ is asymptotically Tregular with respect to f in Y, then ${\{{\alpha}_{1}(d(f{x}_{n},T{x}_{n}))\}}_{n}$ and ${\{{\alpha}_{2}(d(f{x}_{m},T{x}_{m}))\}}_{m}$ are bounded sequences and ${\int}_{0}^{{d}^{r}(f{x}_{n},T{x}_{n})}\psi (t)\phantom{\rule{0.2em}{0ex}}dt\to 0$, ${\int}_{0}^{{d}^{r}(f{x}_{m},T{x}_{m})}\psi (t)\phantom{\rule{0.2em}{0ex}}dt\to 0$, as $n,m\to +\mathrm{\infty}$. This provides the property $H(T{x}_{n},T{x}_{m})\to 0$ as $n,m\to +\mathrm{\infty}$, so that $\{T{x}_{n}\}$ is a Cauchy sequence in $(CB(X),H)$.
If $T(Y)$ is complete, there exists ${K}^{\ast}\in T(Y)\subseteq f(Y)$ such that $H(T{x}_{n},{K}^{\ast})\to 0$ as $n\to +\mathrm{\infty}$. Let $u\in Y$ be such that $f(u)\in {K}^{\ast}$. Then
where the number of terms containing $H({K}^{\ast},T{x}_{n})$ is a finite number depending on r, and therefore fixed. Calculating the limit as $n\to +\mathrm{\infty}$ and taking into account that the length of the intervals in the last integral tends to zero, we get
Therefore,
and, by the properties of ψ, we get ${d}^{r}(fu,Tu)=0$, which implies that $fu\in Tu$ and u is a coincidence point.
Now, suppose that $f(Y)$ is complete. Note that $T{x}_{n}$ is closed and bounded for every $n\in \mathbb{N}$. Take $k>1$ fixed. By the results in [24], we can affirm that for every ${y}_{1}\in T{x}_{n}$, there exists ${y}_{2}\in T{x}_{m}$ such that $d({y}_{1},{y}_{2})\le kH(T{x}_{n},T{x}_{m})$.
Given $n,m\in \mathbb{N}$, we choose ${y}_{1}\in T{x}_{n}$ and, for this ${y}_{1}\in T{x}_{n}$ fixed, we choose ${y}_{2}\in T{x}_{m}$ such that $d({y}_{1},{y}_{2})\le kH(T{x}_{n},T{x}_{m})$. Then
By the hypothesis on $\{{x}_{n}\}$ and the Cauchy character of $\{T{x}_{n}\}$, we deduce that $\{f{x}_{n}\}$ is a Cauchy sequence. Since $f(Y)$ is complete, there exists $f(u)\in f(Y)$ such that $\{f({x}_{n})\}\to f(u)$. By hypotheses, $d(f{x}_{n+k},Tu)\le H(T{x}_{n},Tu)$ for every n, hence
and taking the limit as $n\to +\mathrm{\infty}$, we get
In this case,
and $d(fu,Tu)=0$, which implies that $fu\in Tu$. Now, if f and T are coincidentally idempotent, then $ffw=fw$ for some $w\in C(T,f)$. Hence
Since $ffw=fw\in Tw$, we get
Therefore
obtaining $d(fw,Tfw)=0$ and $fw\in Tfw$. Since $0\le {\int}_{0}^{{H}^{r}(Tfw,Tw)}\psi (t)\phantom{\rule{0.2em}{0ex}}dt\le 0$, we deduce that $H(Tfw,Tw)=0$ and $Tfw=Tw$. In consequence, $ffw=fw\in Tw=Tfw$ and fw is a common fixed point of T and f. □
Remark 25 In the statement of Theorem 24, condition (22) can be replaced by the more general one
To complete the proof with this more general hypothesis, take into account that for $y\in Y$, $T(y)$ is a closed set in X and $T(Y)\subseteq f(Y)$. Using that $f(Y)$ is complete, we deduce that $(CL(f(Y)),H)$ is complete. Hence $\{T{x}_{n}\}$ is a sequence in $CL(f(Y))$ and it is a Cauchy sequence in $(CL(f(Y)),H)$. Therefore, there exists ${K}^{\ast}\in CL(f(Y))$ such that $H(T{x}_{n},{K}^{\ast})\to 0$ as $n\to +\mathrm{\infty}$. Note also that ${K}^{\ast}$ is a closed set in the complete space $f(Y)$, then ${K}^{\ast}$ is complete and, therefore, a closed set, then ${K}^{\ast}\in CL(X)$. Once we have proved that $H(T{x}_{n},{K}^{\ast})\to 0$ as $n\to +\mathrm{\infty}$ in $(CL(f(Y)),H)$, the proof follows analogously.
Theorem 26 In addition to the hypotheses of Theorem 24, suppose that $T{x}_{n}$ is compact for all $n\in \mathbb{N}$. If $f(z)$ is a cluster point of $\{f{x}_{n}\}$, then z is a coincidence point of f and T.
Proof Let ${y}_{n}\in T{x}_{n}$ be such that $d(f{x}_{n},{y}_{n})=d(f{x}_{n},T{x}_{n})\to 0$, this is possible since $T{x}_{n}$ is compact. It is obvious that a cluster point of $\{f{x}_{n}\}$ is a cluster point of $\{{y}_{n}\}$. Let $f(z)$ be a cluster point of $\{f{x}_{n}\}$ and $\{{y}_{n}\}$, then we check that $fz\in Tu$, where u is obtained in the proof of Theorem 24. Note that, for every $y\in Tu$,
hence
In consequence,
Using that there exists a subsequence $f{x}_{{n}_{k}}$ converging to fz, the properties of $\{{x}_{n}\}$ and the inequality
then, taking the limit when ${n}_{k}\to +\mathrm{\infty}$, we get ${\int}_{0}^{{d}^{r}(fz,Tu)}\psi (t)\phantom{\rule{0.2em}{0ex}}dt\le 0$ and $fz\in Tu$. To prove that $fz\in Tz$, using that $fu\in Tu$, we get
This implies that
and, by the properties of ${\alpha}_{2}$ and ψ, we deduce that $d(fz,Tz)=0$, which proves that z is a coincidence point of f and T. □
The following result extends [[10], Theorem 3.3].
Theorem 27 Let Y be an arbitrary nonempty set, $(X,d)$ be a metric space, $f:Y\to X$ and $T:Y\to CB(X)$ be such that (1) and (21) hold, where ${\alpha}_{i}:{\mathbb{R}}_{+}\to [0,1)$ ($i=1,2$) are bounded on bounded sets and such that
r is some fixed positive real number and $\psi :{\mathbb{R}}_{+}\to {\mathbb{R}}_{+}$ is a Lebesgue measurable mapping which is summable on each compact interval, and $\psi (x)>0$ for each $x>0$. Suppose that
If $T(Y)$ is complete or $f(Y)$ is complete, then f and T have a coincidence point. Further, if f and T are occasionally coincidentally idempotent, then f and T have a common fixed point.
Proof Using Theorem 24, it suffices to prove that there exists an asymptotically Tregular sequence $\{{x}_{n}\}$ with respect to f in Y. Let ${x}_{0}\in Y$ and take $\{{x}_{n}\}$ in Y such that $f{x}_{n}\in T{x}_{n1}$ for every $n\in \mathbb{N}$. Then
Hence,
or also, using the hypothesis on ${\alpha}_{1}$ and ${\alpha}_{2}$,
The properties of ψ imply that ${d}^{r}(f{x}_{n},T{x}_{n})\le {d}^{r}(f{x}_{n1},T{x}_{n1})$ for every $n\in \mathbb{N}$, and ${\{d(f{x}_{n},T{x}_{n})\}}_{n\in \mathbb{N}}$ is nonincreasing and bounded below. Therefore it is convergent to the infimum, that is,
and $\{{x}_{n}\}$ is asymptotically Tregular with respect to f in Y. □
Remark 28 Note that condition (23) in Theorem 27 cannot be replaced by
since the infimum taking the sequence $\{{z}_{n}\}$ could be positive (we calculate the infimum in a smaller set).
Remark 29 In Theorem 27, condition (23) can be replaced by the following:
Indeed, since
then
and $d(f{z}_{n},T{z}_{n})\to 0$.
Remark 30 In Theorem 27, if we are able to obtain a sequence $\{{x}_{n}\}$ with an infinite number of terms which are different, then we can relax condition (23) to the following:
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Acknowledgements
Dedicated to Professor Jean Mawhin, on the occasion of his seventieth birthday.
We thank the editor, the anonymous referees and also Professor Stojan Radenović for their helpful comments and suggestions. This research was partially supported by the University Grants Commission, New Delhi, India; Ministerio de Economía y Competitividad, project MTM201015314, and cofinanced by EC fund FEDER.
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Keywords
 coincidence point
 fixed point
 occasionally coincidentally idempotent
 multivalued mappings