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Bounded solutions for the nonlinear wave equation
Boundary Value Problems volume 2013, Article number: 257 (2013)
Abstract
We investigate the number of periodic weak solutions for the wave equation with nonlinearity decaying at the origin. We get a theorem which shows the existence of a bounded weak solution for this problem. We obtain this result by approaching the variational method and applying the critical point theory for the indefinite functional induced from the invariant subspaces and the invariant functional.
MSC:35L05, 35L70.
1 Introduction and statement of the main result
Let g(x,t,u) be a {C}^{1} function from [0,\pi ]\times R\times R to R and Tperiodic in t. In this paper we are concerned with the number of weak periodic solutions of the following wave equation with boundary and periodic conditions:
where T is a rational multiple of π. We assume that g satisfies the following conditions:

(g1)
g\in {C}^{1}([0,\pi ]\times R\times R,R) is Tperiodic in t,

(g2)
g(x,t,0)=0, g(x,t,\xi )=o(\xi ) uniformly with respect to x\in [0,\pi ] and t\in R,

(g3)
there exists C>0 such that g(x,t,\xi )<C \mathrm{\forall}x\in [0,\pi ], t\in R, \xi \in R.
Nonlinear problem of this type has been considered by many authors (cf. [1–5]).
The purpose of this paper is to show the existence of Tperiodic weak solutions of problem (1.1).
Our main result is as follows.
Theorem 1.1 Assume that g satisfies (g1)(g3). Then problem (1.1) has at least one bounded solution.
For the proof of our main result, we approach the variational method and apply the critical point theory induced from the invariant subspaces and the invariant functional. The outline of the proof of Theorem 1.1 is as follows. In Section 2, we introduce two Banach spaces H and E of functions satisfying some symmetry properties, stable by A (Au={u}_{tt}{u}_{xx}), g such that the intersection of H with the kernel of A is reduced to 0. The search of a solution of problem (1.1) in the space H reduces the problem to a situation where {A}^{1} is a compact operator. In Section 3, we introduce a functional I defined on E whose critical points and weak solutions of (1.1) possess onetoone correspondence. We prove that I\in {C}^{1}(E,R) and satisfies the PalaisSmale condition. By a critical point theorem for indefinite functionals (cf. [6]), we prove that there exists at least one solution of (1.1) which is bounded, and we prove Theorem 1.1.
2 Invariant Banach space
Let \mathrm{\Omega}=(0,\pi )\times (0,T); T is a rational multiple of π
where a and b are coprime integers. Let \mathcal{A} be the operator defined by
Let A be the adjoint of \mathcal{A} in {L}^{2}(\mathrm{\Omega}). We investigate the weak solutions of
We note that the eigenvalues of A are {\lambda}_{jk}={j}^{2}{(\frac{2\pi k}{T})}^{2}, j=1,2,\dots and k=0,1,2,\dots , and the corresponding eigenfunctions are
We also note that the set of functions sinjxsin\frac{2\pi kt}{T}, sinjxcos\frac{2\pi kt}{T} is an orthogonal base for {L}^{2}(\mathrm{\Omega}). Let u be a function of {L}^{2}(\mathrm{\Omega}). Then there exists one and only one function of {L}^{2}([0,\pi ]\times R) which is Tperiodic in t and equals u on Ω. We shall denote this function by u. Let us denote an element u, in {L}^{2}(\mathrm{\Omega}), by
with
We assume that b is even and a is odd. Let H be the closed subspace of {L}^{2}(\mathrm{\Omega}) defined by
Then H is invariant under shift: Let h\in H and τ be a real number. If v(x,t)=u(x,t+\tau ), then v\in H. H is invariant under g: Let u\in H such that g(u)\in {L}^{2}(\mathrm{\Omega}). Then g(u)\in H. Let \tilde{u}(x,t)=u(x,t+\frac{T}{2}). Then
Therefore
Let {A}_{1} be a linear operator of H defined by
Then {A}_{1} is selfadjoint in H and H\cap N(A)=\{0\}, where N(A) is the kernel of A. In fact, let u\in H\cap N(A). Then
Let j and k be such that
Since b is even and a is odd, k is even. Using (2.1), we have {u}_{j,k}=0, and therefore H\cap N(A)=\{0\}. The eigenvalues of {A}_{1} are {j}^{2}{(\frac{2\pi k}{T})}^{2}, where j is odd and k is even and H\cap N(A)=\{0\}. Given u\in H, we write
with
Let
where (\phantom{\rule{0.25em}{0ex}},\phantom{\rule{0.25em}{0ex}}) is a scalar product on E. With this scalar product, E is a Hilbert space with a norm
Let
By the classical theorem of Riesz (cf. [[7], p.525]), we have
Since for every \u03f5>o
it follows that for every r\in [2,+\mathrm{\infty}), there is {c}_{r}\in R such that
Let
Then E={E}_{+}\oplus {E}_{}. Let {P}_{+} be the orthogonal projection from E onto {E}_{+} and {P}_{} be the orthogonal projection from E onto {E}_{}. We can write u={P}_{+}u+{P}_{}u for u\in E.
3 Critical point theorem and the proof of Theorem 1.1
Now, we are going to seek a function u in E such that
We consider the associated functional of (3.1),
where
By (g1), I is well defined.
We recall the critical point theorem for the indefinite functional (cf. [6]).
Let
Theorem 3.1 (Critical point theorem for the indefinite functional)
Let E be a real Hilbert space with E={E}_{1}\oplus {E}_{2} and {E}_{2}={E}_{1}^{\perp}. Suppose that I\in {C}^{1}(E,R) satisfies (PS), and that

(I1)
I(u)=\frac{1}{2}(Lu,u)+bu, where Lu={L}_{1}{P}_{1}u+{L}_{2}{P}_{2}u and {L}_{i}:{E}_{i}\to {E}_{i} is bounded and selfadjoint, i=1,2,

(I2)
{b}^{\prime} is compact, and

(I3)
there exist a subspace \tilde{E}\subset E and sets S\subset E, Q\subset \tilde{E} and constants \alpha >\omega such that

(i)
S\subset {E}_{1} and I{}_{S}\ge \alpha,

(ii)
Q is bounded and I{}_{\partial Q}\le \omega,

(iii)
S and ∂Q link.

(i)
Then I possesses a critical value c\ge \alpha.
The eigenvalues of {A}_{1} are {\lambda}_{jk}={j}^{2}{(\frac{2\pi k}{T})}^{2}, where j is odd and k is even, j=1,2,\dots and k=0,1,2,\dots . Thus {A}_{1}^{1} is a compact operator.
It is convenient for the following to rearrange the eigenvalues {\lambda}_{jk}, where j is odd and k is even, by increasing magnitude: from now on we denote by {({\eta}_{i}^{})}_{i\ge 1}={\lambda}_{jk}<0 the sequence of negative eigenvalues, by {({\eta}_{i}^{+})}_{i\ge 1}={\lambda}_{jk}>0 the sequence of positive ones, so that
We note that each eigenvalue has a finite multiplicity and that {\eta}_{i}^{}\to \mathrm{\infty}, {\eta}_{i}^{+}\to +\mathrm{\infty} as i\to \mathrm{\infty}.
We shall show that the functional I satisfies the geometrical assumptions of the critical point theorem for the indefinite functional.
By the following lemma, I(u)\in {C}^{1}(E,R) and the solutions of (3.1) coincide with the nonzero critical points of I(u).
Lemma 3.1 Assume that g satisfies (g1)(g3). Then I(u) is continuous and Fréchet differentiable in E with the Fréchet derivative
for all h\in E. Moreover, if we set
then {F}^{\prime}(u) is continuous with respect to weak convergence, {F}^{\prime}(u) is compact, and
This implies that I\in {C}^{1}(E,R) and F(u) is weakly continuous.
For the proof of Lemma 3.1, refer to [6].
Lemma 3.2 Assume that g satisfies (g1)(g3). The problem
has only a trivial solution.
Proof Let Au={u}_{tt}{u}_{xx}. Since H\cap N(A)=\{0\}, E\cap N(A)=\{0\}. Thus (3.4) has only a trivial solution. □
Lemma 3.3 Assume that g satisfies (g1)(g3). Then I(u) satisfies the PalaisSmale condition: If for a sequence ({u}_{m}), I({u}_{m}) is bounded from above and {I}^{\prime}({u}_{m})\to 0 as m\to \mathrm{\infty}, then ({u}_{m}) has a convergent subsequence.
Proof Let ({u}_{m}) be a sequence with I({u}_{m})\le M and {I}^{\prime}({u}_{m})\to 0 as m\to \mathrm{\infty}. It suffices to show that ({u}_{m}) is bounded. By contradiction, we suppose that \parallel {u}_{m}\parallel \to \mathrm{\infty} as m\to \mathrm{\infty}. Let {w}_{m}=\frac{{u}_{m}}{\parallel {u}_{m}\parallel}. Then \parallel {w}_{m}=1\parallel and {w}_{m} converges weakly to an element, say w. Then we have
Since G(x,t,u) is bounded, letting m∞ in (3.5), we have
On the other hand, we have
Letting m\to \mathrm{\infty} in (3.7), we have
By (3.6) and (3.8), {lim}_{m\to \mathrm{\infty}}{\parallel {P}_{+}{w}_{m}\parallel}^{2}={\parallel {P}_{+}w\parallel}^{2} and {lim}_{m\to \mathrm{\infty}}{\parallel {P}_{}{w}_{m}\parallel}^{2}={\parallel {P}_{}w\parallel}^{2}. Thus {lim}_{m\to \mathrm{\infty}}\parallel {w}_{m}\parallel =\parallel w\parallel, so {w}_{m} converges strongly to w and by (3.8), w is a weak solution of the problem
By Lemma 3.2, w=0, which is absurd for the fact that \parallel w\parallel =1. Thus ({u}_{m}) is bounded. □
Let
Lemma 3.4 Assume that g satisfies the conditions (g1)(g3). There exist a subspace \tilde{E}\subset E and sets \partial {B}_{\rho}\subset E, Q\subset \tilde{E} and constants \rho >0 and \alpha >0 such that

(i)
\partial {B}_{\rho}\subset {E}_{+} and I{}_{\partial {B}_{\rho}}\ge \alpha,

(ii)
there are e\in \partial {B}_{1}\cap {E}_{+} and R>\rho such that if Q=({\overline{B}}_{R}\cap {E}_{})\oplus \{re0<r<R\}, then I{}_{\partial Q}\le 0,

(iii)
there exists {u}_{0}\in E\mathrm{\setminus}Q such that \parallel {u}_{0}\parallel >R and I({u}_{0})\le 0,

(iv)
\partial {B}_{\rho} and ∂Q link.
Proof (i) Let u\in {E}_{+}. Since G(x,t,u) is bounded, there exists a constant C>0 such that
for C>0. Then there exist a constant \rho >0 and a constant \alpha >0 such that if u\in \partial {B}_{\rho}\cap {E}_{+}, then I(u)\ge \alpha.
(ii) Let us choose an element e\in {B}_{1}\cap {E}_{+}. Let u\in ({\overline{B}}_{r}\cap {E}_{})\oplus \{re0<r\}. Then u=v+w, v\in {B}_{r}\cap {E}_{}, w=re. We note that
Thus we have
for {C}_{1}>0. Then there exists R>\rho >0 such that if u\in Q=({\overline{B}}_{R}\cap {E}_{})\oplus \{re0<r<R\}, then I(u){}_{\partial Q}\le 0.
(iii) Let us choose {u}_{0}\in E\mathrm{\setminus}Q. By (ii), I({u}_{0})\le 0.
(iv) S and Q link at the set \{e\}. □
Proof of Theorem 1.1 By Lemma 3.1, I(u) is continuous and Fréchet differentiable in E. By Lemma 3.3, the functional I satisfies the (PS) condition. We note that I(0)=0. By Lemma 3.4, there are constants \rho >0, \alpha >0 and a bounded neighborhood {B}_{\rho} of 0 such that I{}_{\partial {B}_{\rho}\cap {E}_{+}}\ge \alpha, and there are e\in \partial {B}_{1}\cap {E}_{+} and R>\rho such that if Q=({\overline{B}}_{R}\cap {E}_{})\oplus \{re0<r<R\}. Let us set
By Theorem 3.1, I possesses a critical value c\ge \alpha. Moreover, c can be characterized as
Thus we prove that I has at least one nontrivial critical point, we denote by \tilde{u} a critical point of I such that I(\tilde{u})=c. We claim that c is bounded. In fact, we have
and by (g3),
for some constant {C}_{1}>0. Since 0\le \tau \le 1, c is bounded:
We claim that \tilde{u} is bounded. In fact, by contradiction, {\tilde{u}}_{tt}+{\tilde{u}}_{xx}=g(x,t,\tilde{u}) and, for any K>0, {max}_{\mathrm{\Omega}}\tilde{u}(x,t)>K imply that
is not bounded, which is absurd to the fact that c=I(\tilde{u}) is bounded. Thus \tilde{u} is bounded, so (1.1) has at least one bounded weak solution, and hence we prove Theorem 1.1. □
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Acknowledgements
This work (Choi) was supported by Basic Science Research Program through the National Research Foundation of Korea (NRF) funded by the Ministry of Education, Science and Technology (KRF2013010343).
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Jung, T., Choi, QH. Bounded solutions for the nonlinear wave equation. Bound Value Probl 2013, 257 (2013). https://doi.org/10.1186/168727702013257
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DOI: https://doi.org/10.1186/168727702013257