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Third order problems with nonlocal conditions of integral type
Boundary Value Problems volume 2014, Article number: 137 (2014)
Abstract
We discuss the existence of solutions of nonlinear third order ordinary differential equations with integral boundary conditions. We provide sufficient conditions on the nonlinearity and the functions appearing in the boundary conditions that guarantee the existence of at least one solution to our problem. We rely on the method of lower and upper solutions to generate an iterative technique, which is not necessarily monotone.
Introduction
The purpose of this paper is to establish the existence of solutions for a class of nonlinear third order ordinary differential equations with integral boundary conditions. More specifically, we consider the following problem:
where $f:[0,1]\times {\mathbb{R}}^{3}\to \mathbb{R}$, ${h}_{1},{h}_{2}:{\mathbb{R}}^{2}\to \mathbb{R}$ are continuous functions, and $a$ is a nonnegative real number. Several papers have been devoted to the study of third order differential equations with twopoint and threepoint boundary conditions. See [1]–[3], and [4] for references. Problems with integral boundary conditions have been used in the description of many phenomena in the applied sciences. We refer the interested reader to [5] and the references therein. Very few papers have dealt with nonlocal conditions for third order differential equations. We can mention [6], [7] and [8]. For higher order differential equations with functional boundary conditions the interested reader can consult [9]. In this work we use the method of lower and upper solutions to generate a sequence of modified nonlinear problems, each having a unique solution; in this way, we obtain a sequence of functions, which is uniformly bounded together with their first and second order derivatives. We then extract a subsequence converging uniformly to a solution of our original problem (1)(4). Contrary to many works in the literature, we develop an iterative technique, which is not necessary monotone. We should point out that our approach is totally different from that of [9].
Preliminaries
Let $I$ denote the real interval $[0,1]$. $C(I)$ is the Banach space of realvalued continuous functions on $I$, equipped with the norm ${\parallel u\parallel}_{0}:=max\{u(t);t\u03f5I\}$, for $u\in C(I)$. Let $D$ denote the set of all realvalued functions which are three times continuously differentiable on $I$. We define the norm of $u\in D$ by
Let ${D}_{0}=\{u\in D;u(0)=0\}$. Then $({D}_{0},{\parallel \cdot \parallel}_{D})$ is a Banach space.
Definition 1
A solution of problem (1)(4) is a function $u\in {D}_{0}$ that satisfies (1) for every $t\in I$ and the conditions (3) and (4).
Definition 2
Let $\alpha ,\beta \in {D}_{0}$ satisfy ${\alpha}^{\prime}(t)\le {\beta}^{\prime}(t)$ for every $t\in I$. We denote by $[{\alpha}^{\prime},{\beta}^{\prime}]$ the set of all $v\in {D}_{0}$ such that ${\alpha}^{\prime}(t)\le v(t)\le {\beta}^{\prime}(t)$ for every $t\in I$.
It is clear that if ${u}^{\prime}\in [{\alpha}^{\prime},{\beta}^{\prime}]$ and $u\in {D}_{0}$, then $u\in [\alpha ,\beta ]$.
Definition 3
Let $\alpha ,\beta \in {D}_{0}$ satisfy ${\alpha}^{\prime}(t)\le {\beta}^{\prime}(t)$ for every $t\in I$. Let $S(\alpha ,\beta )$ denote the set of all functions $u\in {D}_{0}$ such that $u\in [\alpha ,\beta ]$ and ${u}^{\prime}\in [{\alpha}^{\prime},{\beta}^{\prime}]$.
Remark 1
It is clear that $u\in {D}_{0}$ and ${u}^{\prime}\in [{\alpha}^{\prime},{\beta}^{\prime}]$ imply that $u\in S(\alpha ,\beta )$.
Definition 4
Let $\alpha ,\beta \in {D}_{0}$ satisfy ${\alpha}^{\prime}(t)\le {\beta}^{\prime}(t)$ for every $t\in I$. Define the operator $p:{D}_{0}\to [\alpha ,\beta ]$ by
and the operator $q:{D}_{0}\to [{\alpha}^{\prime},{\beta}^{\prime}]$ by
Remark 2
The operators $p$ and $q$ are continuous and bounded.
Main results
In this section we state and prove our main results. The first result is of independent interest and plays a key role in the proof of our second result.
Theorem 1
Let$\varphi :I\times \mathbb{R}\to \mathbb{R}$be continuous, bounded and satisfy the following condition:
(H_{ ϕ }): $(\varphi (t,{v}_{2})\varphi (t,{v}_{1}))({v}_{2}{v}_{1})<0$for all${v}_{1},{v}_{2}\in \mathbb{R}$such that${v}_{1}\le {v}_{2}$and$t\in I$.
Then for any$\delta $, $\rho $the boundary value problem
has a unique solution$u$.
Proof
Uniqueness. Suppose that problem (5) has two solutions $x$ and $u$ in ${D}_{0}$. Put $z={x}^{\prime}{u}^{\prime}$. Then $z(1)={x}^{\prime}(1){u}^{\prime}(1)=0$. We show that $z(0)=0$. Suppose this is not true. Then either $z(0)>0$ or $z(0)<0$. We consider the case $z(0)>0$. From the condition at $t=0$ it follows that $0<z(0)=a{z}^{\prime}(0)$. Since $a$ is nonnegative we have ${z}^{\prime}(0)>0$, which implies that $z$ is increasing to the right of $t=0$. Since $z(1)=0$ there must exist $\xi \in [0,1)$ such that $z(\xi )={max}_{t\in I}z(t)$. Then
The differential equation in (5) and (H_{ ϕ }) imply
This is a contradiction. Similarly, if we consider the case $z(0)<0$ we will arrive at a contradiction. Hence $z(0)=0$. Now, we have a function $z$ continuous on $I$ with $z(0)=z(1)=0$. Then there exists $\tau \in I$ such that
Proceeding as before we show that $z(\tau )=0$. So that $z(t)=0$ for all $t\in I$. This shows that ${x}^{\prime}(t)={u}^{\prime}(t)$ for all $t\in I$. Since $x(0)=u(0)=0$ it follows that $x(t)=u(t)$ for all $t\in I$, which shows the uniqueness of the solution.
Existence. For $\lambda \in [0,1]$ consider the family of problems
For $\lambda =0$ problem (6) has only the trivial solution. Thus, we consider the case $\lambda \in (0,1]$.

(i)
$u$ is a solution of (6) if and only if it satisfies, for all $t\in I$,
$$\begin{array}{rcl}u(t)& =& \frac{\lambda t}{a+1}(\delta +a\rho +a{\int}_{0}^{1}(1s)\varphi (s,{u}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds)\\ +\frac{\lambda {t}^{2}}{2(a+1)}(\rho \delta +{\int}_{0}^{1}(1s)\varphi (s,{u}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds)\\ \lambda {\int}_{0}^{t}\frac{{(ts)}^{2}}{2}\varphi (s,{u}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds.\end{array}$$(7)Indeed, it is clear that the differential equation in (6) implies
$$u(t)={u}^{\prime}(0)t+{u}^{\u2033}(0)\frac{{t}^{2}}{2}\lambda {\int}_{0}^{t}\frac{{(ts)}^{2}}{2}\varphi (s,{u}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds.$$(8)Then
$${u}^{\prime}(t)={u}^{\prime}(0)+{u}^{\u2033}(0)t\lambda {\int}_{0}^{t}(ts)\varphi (s,{u}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds.$$(9)It follows that
$$\lambda \rho ={u}^{\prime}(1)={u}^{\prime}(0)+{u}^{\u2033}(0)\lambda {\int}_{0}^{1}(1s)\varphi (s,{u}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds.$$But ${u}^{\prime}(0)=a{u}^{\u2033}(0)+\lambda \delta $, so that
$${u}^{\u2033}(0)=\frac{\lambda}{a+1}[\rho \delta +{\int}_{0}^{1}(1s)\varphi (s,{u}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds],$$and consequently
$${u}^{\prime}(0)=\frac{\lambda}{a+1}[\delta +a\rho +a{\int}_{0}^{1}(1s)\varphi (s,{u}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds].$$Now, substitute the expressions of ${u}^{\prime}(0)$ and ${u}^{\u2033}(0)$ into (8) to get (7).

(ii)
We show that there exists a positive constant ${L}_{0}$, independent of $\lambda $, such that any possible solution $u$ of (6) satisfies
$${\parallel u\parallel}_{D}\le {L}_{0}.$$(10)The boundedness of $\varphi $ implies that there exists ${M}_{\varphi}>0$ such that $\varphi (t,{u}^{\prime}(t))\le {M}_{\varphi}$ for all $t\in I$, so that ${\parallel {u}^{\u2034}\parallel}_{0}\le {M}_{\varphi}$. Then
$${u}^{\prime}(0)\le \frac{1}{a+1}[\delta +a\rho +a\frac{{M}_{\varphi}}{2}]$$(11)and
$${u}^{\u2033}(0)\le \frac{1}{a+1}[\delta +\rho +\frac{{M}_{\varphi}}{2}].$$(12)Combining relations (9), (11), and (12) we see that
$${\parallel {u}^{\prime}\parallel}_{0}\le {M}_{2}:=\frac{1}{a+1}[2\delta +(a+1)\rho +(a+1){M}_{\varphi}].$$(13)Since $u(t)={\int}_{0}^{t}{u}^{\prime}(s)\phantom{\rule{0.2em}{0ex}}ds$ it follows that
$${\parallel u\parallel}_{0}\le {M}_{2}.$$Also, ${\parallel {u}^{\u2034}\parallel}_{0}\le {M}_{\varphi}$ and (12) imply
$${\parallel {u}^{\u2033}\parallel}_{0}\le {M}_{1}:=\frac{1}{a+1}[\delta +\rho +\frac{(2a+3){M}_{\varphi}}{2}].$$Let ${L}_{0}={M}_{1}+2{M}_{2}+{M}_{\varphi}$. Then any possible solution $u$ of (6) satisfies (10).

(iii)
Define an operator $\mathrm{\Psi}:{D}_{0}\to {D}_{0}$ by $(\mathrm{\Psi}u)(t)$ = the righthand side of (7). Let $\mathrm{\Omega}:=\{u\in {D}_{0};{\parallel u\parallel}_{D}\le {L}_{0}\}$. Then it is easily seen that $(\mathrm{\Psi}(\mathrm{\Omega}))$ is uniformly bounded and equicontinuous. AscoliArzela theorem implies that the operator $\mathrm{\Psi}$ is compact. Moreover, the set of all solutions $u$ of the equation $u=\lambda \mathrm{\Psi}u$ is bounded (see (10)). It follows from Schaefer theorem (see [10]) that $u=\mathrm{\Psi}u$ has at least one solution. Thus, (6) has at least one solution for $\lambda =1$, which is, in fact, unique from the previous step. Thus, $u$ is a solution of (5). This completes the proof of the theorem. □
Remark 3
We should emphasize that, unlike Theorem 6 in [9], our Theorem 1 gives the uniqueness of the solution and this is essentially utilized in the proof of our Theorem 2 below.
For our second main result we introduce the notion of lower and upper solutions of problem (1), (2), (3), (4).
Definition 5

(a)
We say that $\alpha \in {D}_{0}$ is a lower solution of problem (1), (3), (4) if
$$\{\begin{array}{l}{\alpha}^{\u2034}(t)\le f(t,\alpha (t),{\alpha}^{\prime}(t),{\alpha}^{\u2033}(t))\phantom{\rule{1em}{0ex}}\text{for all}t\in I,\\ {\alpha}^{\prime}(0)a{\alpha}^{\u2033}(0)\le {\int}_{0}^{1}{h}_{1}(\alpha (s),{\alpha}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds,\\ {\alpha}^{\prime}(1)\le {\int}_{0}^{1}{h}_{2}(\alpha (s),{\alpha}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds.\end{array}$$ 
(b)
We say that $\beta \in {D}_{0}$ is an upper solution of problem (1), (3), (4) if
$$\{\begin{array}{l}{\beta}^{\u2034}(t)\ge f(t,\beta (t),{\beta}^{\prime}(t),{\beta}^{\u2033}(t))\phantom{\rule{1em}{0ex}}\text{for all}t\in I,\\ {\beta}^{\prime}(0)a{\beta}^{\u2033}(0)\ge {\int}_{0}^{1}{h}_{1}(\beta (s),{\beta}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds,\\ {\beta}^{\prime}(1)\ge {\int}_{0}^{1}{h}_{2}(\beta (s),{\beta}^{\prime}(s))\phantom{\rule{0.2em}{0ex}}ds.\end{array}$$
To state and prove our second main result we introduce the following assumptions.
(A_{ f }): $f:I\times {\mathbb{R}}^{3}\to \mathbb{R}$ is continuous and satisfies

(1)
there exists ${C}_{0}>0$ such that any solution $u$ of (1), with $u\in S(\alpha ,\beta )$, satisfies ${u}^{\u2033}(t)\le {C}_{0}$, for all $t\in I$;

(2)
$(f(t,u(t),{v}_{2},w)f(t,u(t),{v}_{1},w))({v}_{2}{v}_{1})<0$ for ${v}_{1},{v}_{2}\in \mathbb{R}$ such that ${v}_{1}\le {v}_{2}$, $u\in D\cap [\alpha ,\beta ]$, $w\in \mathbb{R}$ and $t\in I$;

(3)
$f(t,\alpha (t),v(t),{\alpha}^{\u2033}(t))\le f(t,u(t),v(t),w)\le f(t,\beta (t),v(t),{\beta}^{\u2033}(t))$ for all $u\in D\cap [\alpha ,\beta ]$, $v\in {C}^{2}\cap [{\alpha}^{\prime},{\beta}^{\prime}]$, $w\in \mathbb{R}$, and $t\in I$.
(A_{ h }): ${h}_{1},{h}_{2}:{\mathbb{R}}^{2}\to \mathbb{R}$ are continuous and nondecreasing with respect to both arguments.
Remark 4
There are several sufficient conditions that imply (A_{ f })(1). See for instance [6], Lemma 1], [3], Lemma 1].
Theorem 2
Let$\alpha ,\beta \in {D}_{0}$be, respectively, a lower and an upper solution of problem (1), (3), (4) such that${\alpha}^{\prime}\le {\beta}^{\prime}$on$I$. Assume that the conditions (A_{ f }) and (A_{ h }) are satisfied for the pair$(\alpha ,\beta )$, where$\alpha $is a given lower solution and$\beta $is a given upper solution. Then problem (1), (3), (4) has at least one solution$u\in S(\alpha ,\beta )$.
Proof
We modify problem (1), (2), (3), (4) as follows. We define two functions ${f}_{{C}_{0}},F:I\times {\mathbb{R}}^{3}\to \mathbb{R}$ by
and
where ${C}_{0}$ is the constant from condition (A_{ f })(1). Consider the modified problem
Define a sequence ${({u}_{j})}_{j\in \mathbb{N}}$ of functions in ${D}_{0}$ as follows. Let
where $\gamma ={max}_{t\in I}({\alpha}^{\prime}{\beta}^{\prime})(t)$, and for $j\ge 1$,
We shall show that the sequence of modified problems (17) is such that each problem has a unique solution, which is uniformly bounded, together with its first and second order derivatives. Then we rely on BolzanoWeierstrass theorem to extract a uniformly convergent subsequence, whose limit is the solution of our original problem.

1.
The sequence ${({u}_{j})}_{j\in \mathbb{N}}$ is well defined. Indeed, for any $t\in I$ and any $z\in \mathbb{R}$ we have $q(z)\in [{\alpha}^{\prime},{\beta}^{\prime}]$ and $p({u}_{j1}(t))\in [\alpha ,\beta ]$. It follows that the function $\varphi :I\times \mathbb{R}\to \mathbb{R}$, defined by
$$\varphi (t,z)=F(t,{u}_{j1}(t),z,{u}_{j1}^{\prime \prime}(t))=f(t,p({u}_{j1})(t),q(z),{u}_{j1}^{\prime \prime}(t)),$$is continuous and bounded for all $t\in I$ and $z\in \mathbb{R}$. Moreover, condition (A_{ f })(2) shows that $\varphi $ satisfies condition (H_{ ϕ }) in Theorem 1. It follows from this theorem that (17) has a unique solution ${u}_{j}$, for each $j=1,2,\dots $ .

2.
For each $j=0,1,\dots $ the functions ${u}_{j}$ satisfy ${u}_{j}\in S(\alpha ,\beta )$ and the sequence ${({u}_{j}^{\prime \prime})}_{j\in \mathbb{N}}$ is uniformly bounded.
It is clear that ${u}_{j}\in {D}_{0}$ for $j=0,1,\dots $ . Since ${\alpha}^{\prime}\le {\beta}^{\prime}$ it follows that $\gamma \le 0$, so that ${u}_{0}^{\prime}=\gamma +{\beta}^{\prime}\le {\beta}^{\prime}$. On the other hand, we have $\gamma \ge {min}_{t\in I}({\beta}^{\prime}{\alpha}^{\prime})(t)\ge {\beta}^{\prime}(t)+{\alpha}^{\prime}(t)$; so that ${u}_{0}^{\prime}\ge {\alpha}^{\prime}$. It follows that ${u}_{0}^{\prime}\in [{\alpha}^{\prime},{\beta}^{\prime}]$, and consequently ${u}_{0}\in S(\alpha ,\beta )$. Also, since ${u}_{0}^{\prime \prime}={\beta}^{\u2033}$ then ${\parallel {u}_{0}^{\prime \prime}\parallel}_{0}\le {\parallel {\beta}^{\u2033}\parallel}_{0}$. Suppose, by induction, that we have ${u}_{\ell 1}\in S(\alpha ,\beta )$ and there exists ${K}_{1}\le {C}_{0}$ such that ${\parallel {u}_{\ell 1}^{\prime \prime}\parallel}_{0}\le {K}_{1}$. Let
Claim 1. There exists $K$ depending only on ${K}_{1}$, ${M}_{f}$, $\overline{h}$, ${\parallel {\alpha}^{\u2033}\parallel}_{0}$, and ${\parallel {\beta}^{\u2033}\parallel}_{0}$ such that ${\parallel {u}_{\ell}^{\prime \prime}\parallel}_{0}\le K$ and ${u}_{\ell}\in S(\alpha ,\beta )$.
To prove the claim we start with
which leads to
The boundary conditions imply
On the other hand
It is readily seen that
Since ${u}_{\ell 1}^{\prime \prime}(1)\le {K}_{1}$ (by the induction hypothesis) it follows that
It follows from (18) and (19) that
Claim 2. ${u}_{\ell}\in S(\alpha ,\beta )$. Since ${u}_{\ell}(0)=0$ it suffices to show that ${u}_{\ell}^{\prime}\in [{\alpha}^{\prime},{\beta}^{\prime}]$, i.e.${\alpha}^{\prime}\le {u}_{\ell}^{\prime}\le {\beta}^{\prime}$. We, first, prove that ${\alpha}^{\prime}\le {u}_{\ell}^{\prime}$. For this purpose, set $W(t)={u}_{\ell}^{\prime}(t){\alpha}^{\prime}(t)$, for $t\in I$. We show that $W(t)\ge 0$ for all $t\in I$. Suppose by contradiction, that there exists ${\xi}_{1}\in I$ such that $W({\xi}_{1})<0$. Since $W$ is continuous, it follows that there exists $\eta \in I$ such that $W(\eta )=min\{W(t);t\in I\}<0$. Hence we have $W(\eta )<0$, ${W}^{\prime}(\eta )=0$ and ${W}^{\u2033}(\eta )>0$. Thus,
But $W(\eta )={u}_{\ell}^{\prime}(\eta ){\alpha}^{\prime}(\eta )<0$ and ${W}^{\prime}(\eta )={u}_{\ell}^{\prime \prime}(\eta ){\alpha}^{\u2033}(\eta )=0$. Therefore, $q({u}_{\ell}^{\prime}(\eta ))={\alpha}^{\prime}(\eta )$ and ${u}_{\ell}^{\prime \prime}(\eta )={\alpha}^{\u2033}(\eta )$. Hence,
It follows that
Since
we infer that
The above inequality is not possible by (A_{ f })(3). Now, if $\eta =0$, then $W(0)<0$, ${W}^{\prime}(0)\ge 0$, and ${W}^{\u2033}(0)\ge 0$. It follows that
Since
we get
The monotonicity of ${h}_{1}$ leads to
This is not possible by the properties of the lower solution $\alpha $. Finally, $W(1)\ge 0$. Indeed,
by definition of the lower solution $\alpha $. Similarly we show that ${u}_{\ell}^{\prime}\le {\beta}^{\prime}$. Thus, we have shown that ${u}_{\ell}^{\prime}\in [{\alpha}^{\prime},{\beta}^{\prime}]$, which implies that ${u}_{\ell}\in S(\alpha ,\beta )$. Therefore, we have proved that the sequences ${({u}_{j}^{\prime \prime})}_{j\in \mathbb{N}}$, ${({u}_{j}^{\prime})}_{j\in \mathbb{N}}$, and ${({u}_{j})}_{j\in \mathbb{N}}$ are uniformly bounded on the interval $I$. BolzanoWeierstrass theorem implies that we can extract subsequences ${({u}_{{j}_{m}}^{\prime \prime})}_{{j}_{m}\in \mathbb{N}}$, ${({u}_{{j}_{m}}^{\prime})}_{{j}_{m}\in \mathbb{N}}$ and ${({u}_{{j}_{m}})}_{{j}_{m}\in \mathbb{N}}$ that are uniformly convergent on $I$. Using the diagonalization process, if necessary, we shall assume that ${lim}_{m\to \mathrm{\infty}}{u}_{{j}_{m}}^{\prime \prime}={lim}_{m\to \mathrm{\infty}}{u}_{{j}_{m1}}^{\prime \prime}=w$, ${lim}_{m\to \mathrm{\infty}}{u}_{{j}_{m}}^{\prime}={lim}_{m\to \mathrm{\infty}}{u}_{{j}_{m1}}^{\prime}=v$ and ${lim}_{m\to \mathrm{\infty}}{u}_{{j}_{m}}={lim}_{m\to \mathrm{\infty}}{u}_{{j}_{m1}}=u$. To complete the proof of our second main result we prove that ${u}^{\prime}=v$, ${u}^{\u2033}=w$ and $u$ is the desired solution of our original problem. Since ${u}_{{j}_{m}}(t)={\int}_{0}^{t}{u}_{{j}_{m}}^{\prime}(s)\phantom{\rule{0.2em}{0ex}}ds$, it follows from the uniform convergence of the two subsequences that $u(t)={\int}_{0}^{t}v(s)\phantom{\rule{0.2em}{0ex}}ds$, and this equality implies that $u(0)=0$ and ${u}^{\prime}=v$. Also, we have ${u}_{{j}_{m}}(t)={u}_{{j}_{m}}(0)+{u}_{{j}_{m}}^{\prime}(0)t+{\int}_{0}^{t}(ts){u}_{{j}_{m}}^{\prime \prime}(s)\phantom{\rule{0.2em}{0ex}}ds={u}_{{j}_{m}}^{\prime}(0)t+{\int}_{0}^{t}(ts){u}_{{j}_{m}}^{\prime \prime}(s)\phantom{\rule{0.2em}{0ex}}ds$, which implies that $u(t)={u}^{\prime}(0)t+{\int}_{0}^{t}(ts)w(s)\phantom{\rule{0.2em}{0ex}}ds$, from which we readily get ${u}^{\u2033}=w$. It is clear that
The differential equation ${u}_{{j}_{m}}^{\prime \prime \prime}(t)=F(t,{u}_{{j}_{m}1}(t),{u}_{{j}_{m}}^{\prime}(t),{u}_{{j}_{m}1}^{\prime \prime}(t))$, for $t\in I$, implies that ${u}_{{j}_{m}}^{\prime \prime}(t)={u}_{{j}_{m}}^{\prime \prime}(0)+{\int}_{0}^{t}F(s,{u}_{{j}_{m}1}(s),{u}_{{j}_{m}}^{\prime}(s),{u}_{{j}_{m}1}^{\prime \prime}(s))\phantom{\rule{0.2em}{0ex}}ds$. The continuity of $F$ and the uniform convergence of the respective subsequences imply that ${u}^{\u2033}(t)={u}^{\u2033}(0)+{\int}_{0}^{t}F(s,u(s),{u}^{\prime}(s),{u}^{\u2033}(s))\phantom{\rule{0.2em}{0ex}}ds$, so that
The definition of $F$ and (21) show that
Similarly we can show that
and
We see that $u$ is a solution of (1), (2), (3), (4). Moreover, $u\in S(\alpha ,\beta )$. This completes the proof of our main result. □
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Acknowledgements
A Boucherif is grateful to King Fahd University of Petroleum and Minerals for its constant support. The authors are grateful to the anonymous referees and the handling editor for comments that led to the improvement of the presentation of the manuscript.
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Boucherif, A., Bouguima, S.M., Benbouziane, Z. et al. Third order problems with nonlocal conditions of integral type. Bound Value Probl 2014, 137 (2014). https://doi.org/10.1186/s136610140137z
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Keywords
 third order differential equations
 integral boundary conditions
 a priori bound on solutions
 fixed point theorems
 lower and upper solutions
 iterative technique
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